Exception Handling: ArrayIndexOutOfBoundsException

In this problem, you will implement a static method accessArray(int index) that accesses elements in the array {10, 20, 30} by index. For valid indices, it returns the element value. For invalid indices, ArrayIndexOutOfBoundsException is thrown naturally.

Learning Objective: Understand how exceptions occur during array index access and learn to catch them using try-catch statements

Overview

In Java, accessing an array index outside the valid range (0 to length-1) automatically throws an ArrayIndexOutOfBoundsException. By implementing this method, you will understand when exceptions occur and learn how callers can handle them using try-catch.

Specifications

Implement the following static field and method:

static int[] array = {10, 20, 30};

static int accessArray(int index) {
    // Return the array element at the given index
    // Throws ArrayIndexOutOfBoundsException for invalid indices
}

Test Cases

Call	Result
accessArray(0)	Returns 10
accessArray(2)	Returns 30
accessArray(5)	ArrayIndexOutOfBoundsException
accessArray(-1)	ArrayIndexOutOfBoundsException

Hint

• Valid array indices are from 0 to array.length - 1
• For invalid indices, the Java runtime automatically throws an exception
• Try using try-catch in the main method to observe the behavior